Source

CheckIO / Elementary / Python / Fizz Buzz

Description

Given a positive integer n, return:

  • “Fizz” if n is divisible by 3
  • “Buzz” if n is divisible by 5
  • “FizzBuzz” if n is divisible by 3 and by 5
  • A string representation of the number in any other case
1
2
3
4

6 ⟹ "Fizz"
5 ⟹ "Buzz"
15 ⟹ "FizzBuzz"
7 ⟹ "7"

My solution

1
2
3
4
5
6
7
8
9
10
11
12

public class fizzbuzzSingle {
    
    public static String fizzbuzz(int n) {
        String nstr = String.valueOf(n);
        String result = "";
        if (n < 0) return nstr;
        if (n % 3 == 0) result = "Fizz";
        if (n % 5 == 0) result += "Buzz";
        return result.length() > 0 ? result : nstr;
    }

}

Tests

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27

import org.junit.*;
import static org.junit.Assert.*;

public class fizzbuzzSingleTest {
    fizzbuzzSingle x = new fizzbuzzSingle();

    @Test
    public void testNegative() {
        assertEquals(x.fizzbuzz(-1), "-1");
    }
    
    @Test
    public void testFizz() {
        assertEquals(x.fizzbuzz(6), "Fizz");
    }
    
    @Test
    public void testBuzz() {
        assertEquals(x.fizzbuzz(5), "Buzz");
    }
    
    @Test
    public void testFizzBuzz() {
        assertEquals(x.fizzbuzz(15), "FizzBuzz");
    }

}